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-rw-r--r--main.asm54
1 files changed, 53 insertions, 1 deletions
diff --git a/main.asm b/main.asm
index f6b68cfbf..52ae27f82 100644
--- a/main.asm
+++ b/main.asm
@@ -365,7 +365,59 @@ CountSetBits: ; 0x335f
ret
; 0x3376
-INCBIN "baserom.gbc",$3376,$38f2 - $3376
+INCBIN "baserom.gbc",$3376,$38bb - $3376
+
+PrintBCDNumber: ; 38bb
+; function to print a BCD (Binary-coded decimal) number
+; de = address of BCD number
+; hl = destination address
+; c = flags and length
+; bit 7: if set, do not print leading zeroes
+; if unset, print leading zeroes
+; bit 6: if set, left-align the string (do not pad empty digits with spaces)
+; if unset, right-align the string
+; bit 5: if set, print currency symbol at the beginning of the string
+; if unset, do not print the currency symbol
+; bits 0-4: length of BCD number in bytes
+; Note that bits 5 and 7 are modified during execution. The above reflects
+; their meaning at the beginning of the functions's execution.
+ ld b, c ; save flags in b
+ res 7, c
+ res 6, c
+ res 5, c ; c now holds the length
+ bit 5, b
+ jr z, .loop\@
+ bit 7, b
+ jr nz, .loop\@
+ ld [hl], "¥"
+ inc hl
+.loop\@
+ ld a, [de]
+ swap a
+ call PrintBCDDigit ; print upper digit
+ ld a, [de]
+ call PrintBCDDigit ; print lower digit
+ inc de
+ dec c
+ jr nz, .loop\@
+ bit 7, b ; were any non-zero digits printed?
+ jr z, .done\@ ; if so, we are done
+.numberEqualsZero\@ ; if every digit of the BCD number is zero
+ bit 6, b ; left or right alignment?
+ jr nz, .skipRightAlignmentAdjustment\@
+ dec hl ; if the string is right-aligned, it needs to be moved back one space
+.skipRightAlignmentAdjustment\@
+ bit 5, b
+ jr z, .skipCurrencySymbol\@
+ ld [hl], "¥" ; currency symbol
+ inc hl
+.skipCurrencySymbol\@
+ ld [hl], "0"
+ call PrintLetterDelay
+ inc hl
+.done\@
+ ret
+; 0x38f2
PrintBCDDigit: ; 38f2
and a, %00001111